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Smallest town in US sold for 900k dollars at auction


April 6, 2012 - London

A town in the state of Wyoming, USA - said to be the smallest in the country - has been sold at an auction for 900,000 dollars.

Two unidentified Vietnamese men placed the winning bid for Buford on Thursday, the BBC reported.

The town includes a school house, a petrol station, a three-bedroom home with a cabin and a general store.

Don Sammons, Buford's ex-owner and only resident, auctioned it at a starting price of 100,000 dollars.

Sammons, 60, has lived in the town since 1980, is quitting his unofficial role as "mayor" to move on.

When his son moved away several years ago, Sammons became Buford's only resident.

The second oldest town in Wyoming, Buford is on Interstate 80, the main cross-country road from New York to San Francisco.

The unincorporated community sits between Laramie and Cheyenne, the Wyoming state capital, at an altitude of 8,000 ft. It comes with its own zip code and US postal boxes.

According to the auction house, it also has a mobile phone tower and about 10 acres of land, much of which is fenced.

The establishment of Buford dates back to the construction of the transcontinental railroad and it at one time had a population of about 2,000.

ANI

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